Initializes a new instance of the
MedicalViewerOffset class with specified x and y offsets.
Syntax
| Visual Basic (Declaration) | |
|---|
Public Function New( _
ByVal x As Integer, _
ByVal y As Integer _
) |
| C# | |
|---|
public MedicalViewerOffset(
int x,
int y
) |
| C++/CLI | |
|---|
public:
MedicalViewerOffset(
int x,
int y
) |
Parameters
- x
- the x offset of the image.
- y
- the y offset of the image.
Example
Change the offset of the image of the first cell
| Visual Basic |  Copy Code |
|---|
<Test> _
Public Sub MedicalViewerOffset3()
Dim myForm As MedicalViewerForm = GetMedicalControl()
Dim medicalViewer As MedicalViewer = myForm.Viewer
Dim offset As MedicalViewerOffset = New MedicalViewerOffset(50, 50)
medicalViewer.SetActionProperties(MedicalViewerActionType.Offset, offset, 0)
myForm.ShowDialog()
End Sub |
| C# | Copy Code |
|---|
public void MedicalViewerOffset3()
{
MedicalViewerForm myForm = GetMedicalControl();
MedicalViewer medicalViewer = myForm.Viewer;
MedicalViewerOffset offset = new MedicalViewerOffset(50, 50);
medicalViewer.SetActionProperties(MedicalViewerActionType.Offset, offset, 0);
myForm.ShowDialog();
} |
Requirements
Target Platforms: Microsoft .NET Framework 2.0, Windows 98, Windows NT 4.0, Windows Millennium Edition, Windows 2000, Windows XP Home Edition, Windows XP Professional, Windows Server 2003 family
See Also
