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FriendlyName Property
See Also 
Leadtools.Multimedia Namespace > Device Class : FriendlyName Property



Gets the device's descriptive name.

Syntax

Visual Basic (Declaration) 
Public ReadOnly Property FriendlyName As String
Visual Basic (Usage)Copy Code
Dim instance As Device
Dim value As String
 
value = instance.FriendlyName
C# 
public string FriendlyName {get;}
C++/CLI 
public:
property String^ FriendlyName {
   String^ get();
}

Property Value

the device's friendly name.

Example

Visual BasicCopy Code
Public _result As Boolean = False
Public _form As CaptureCtrlForm = New CaptureCtrlForm()
Public Sub DevicesExample()
  Dim inputName, inputFriendlyName As String
  Dim selection As Integer

  ' reference the capture control
  Dim capturectrl As CaptureCtrl = _form.CaptureCtrl

  ' select a video device, use your device name here instead of Analog
  If capturectrl.VideoDevices("Analog") Is Nothing Then
     Throw New Exception("No Analog video tuner device available")
  End If

  capturectrl.VideoDevices("Analog").Selected = True

  ' get the audio inputs object
  Dim devices As Devices = capturectrl.VideoDevices

  Try
     ' select an input by name if possible
     If Not devices("USB") Is Nothing Then
       devices("USB").Selected = True
     End If

     ' get the current selected input
     selection = devices.Selection

     For Each dev As Device In devices
       ' get the inputs properties
       inputName = dev.Name
       inputFriendlyName = dev.FriendlyName

       ' if we found a digital video capture device
       If inputFriendlyName.Contains("Digital") Then
         ' select it and break
         dev.Selected = True
         Exit For
       End If
     Next dev

     ' set the result to what we expect
     _result = (selection <> devices.Selection)

  Catch e1 As Exception
     _result = False
  End Try
End Sub
C#Copy Code
public bool _result = false;
public CaptureCtrlForm _form = new CaptureCtrlForm();
public void DevicesExample()
{
   string inputName, inputFriendlyName;
   int selection;

   // reference the capture control
   CaptureCtrl capturectrl = _form.CaptureCtrl;

   // select a video device, use your device name here instead of Analog
   if (capturectrl.VideoDevices["Analog"] == null)
      throw new Exception("No Analog video tuner device available");

   capturectrl.VideoDevices["Analog"].Selected = true;

   // get the audio inputs object
   Devices devices = capturectrl.VideoDevices;

   try
   {
      // select an input by name if possible
      if (devices["USB"] != null)
         devices["USB"].Selected = true;

      // get the current selected input
      selection = devices.Selection;

      foreach (Device dev in devices)
      {
         // get the inputs properties
         inputName = dev.Name;
         inputFriendlyName = dev.FriendlyName;

         // if we found a digital video capture device
         if (inputFriendlyName.Contains("Digital"))
         {
            // select it and break
            dev.Selected = true;
            break;
         }
      }

      // set the result to what we expect
      _result = (selection != devices.Selection);

   }
   catch (Exception)
   {
      _result = false;
   }
}

Remarks

The returned name is not unique. However, it is ideal for presenting a descriptive name in user interfaces.

Requirements

Target Platforms: Microsoft .NET Framework 2.0, Windows 2000, Windows XP, Windows Server 2003 family, Windows Server 2008 family, Windows Vista, Windows 7

See Also