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LEADTOOLS Vector C++ Class Library Help

LVectorBase::GetLayerByName

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#include "ltwrappr.h"

virtual L_INT LVectorBase::GetLayerByName(pszName, pVectorLayer)

const L_TCHAR *pszName;

/* layer name */

LVectorLayer * pVectorLayer;

/* pointer to a vector layer object */

Gets the layer with the specified name, in the class object's associated vector handle.

Parameter

Description

pszName

Character string that contains the name of the layer to get.

pVectorLayer

Pointer to an LVectorLayer object structure to be updated with the layer handle, if the layer is found. If the layer is not found, this function will return ERROR_VECTOR_LAYER_NOT_FOUND.

Returns

SUCCESS

The function was successful.

< 1

An error occurred. Refer to Return Codes.

Comments

If two or more layers in a vector handle have the same name, this function will get the first layer found.

Required DLLs and Libraries

LVKRN

For a listing of the exact DLLs and Libraries needed, based on the toolkit version, refer to Files To Be Included With Your Application.

See Also

Functions:

LVectorBase::GetLayerCount, LVectorBase::GetLayerByIndex

Topics:

Working with Vector Layers

Example

This example will get a layer by name.

L_INT LVectorBase__GetLayerByNameExample(HWND hWnd, LVectorBase *pVector)
{
   UNREFERENCED_PARAMETER(hWnd);
   L_INT          nRet;
   LVectorLayer   VectorLayer;
   L_TCHAR        szMsg[100];
   //Get the layer called "Sphere3"
   nRet = pVector->GetLayerByName(TEXT("Sphere3"), &VectorLayer);
   if (nRet == SUCCESS)
   {
      VECTORLAYERDESC LayerDesc;
      nRet = VectorLayer.GetLayerDesc(&LayerDesc);
      if(nRet != SUCCESS)
         return nRet;
      wsprintf(szMsg, TEXT("Layer Retrieved\nName[%s]\nSize[%d]\nLocked[%d]\nVisible[%d]"),
         LayerDesc.szName,
         LayerDesc.nSize,
         LayerDesc.bLocked,
         LayerDesc.bVisible
         );
   }
   else
   {
      wsprintf(szMsg, TEXT("Layer Not Found"));
      return nRet;
   }
   MessageBox(NULL, szMsg, TEXT(""), MB_OK);
   return SUCCESS;
}
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