LEADTOOLS Vector C++ Class Library Help > Classes and Member Functions > LVectorBase > LVectorBase Class Members > LVectorBase::GetLayerByName |
#include "ltwrappr.h"
virtual L_INT LVectorBase::GetLayerByName(pszName, pVectorLayer)
const L_TCHAR *pszName; |
/* layer name */ |
LVectorLayer * pVectorLayer; |
/* pointer to a vector layer object */ |
Gets the layer with the specified name, in the class object's associated vector handle.
Parameter |
Description |
pszName |
Character string that contains the name of the layer to get. |
pVectorLayer |
Pointer to an LVectorLayer object structure to be updated with the layer handle, if the layer is found. If the layer is not found, this function will return ERROR_VECTOR_LAYER_NOT_FOUND. |
Returns
SUCCESS |
The function was successful. |
< 1 |
An error occurred. Refer to Return Codes. |
Comments
If two or more layers in a vector handle have the same name, this function will get the first layer found.
Required DLLs and Libraries
LVKRN For a listing of the exact DLLs and Libraries needed, based on the toolkit version, refer to Files To Be Included With Your Application. |
See Also
Functions: |
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Topics: |
Example
This example will get a layer by name.
L_INT LVectorBase__GetLayerByNameExample(HWND hWnd, LVectorBase *pVector) { UNREFERENCED_PARAMETER(hWnd); L_INT nRet; LVectorLayer VectorLayer; L_TCHAR szMsg[100]; //Get the layer called "Sphere3" nRet = pVector->GetLayerByName(TEXT("Sphere3"), &VectorLayer); if (nRet == SUCCESS) { VECTORLAYERDESC LayerDesc; nRet = VectorLayer.GetLayerDesc(&LayerDesc); if(nRet != SUCCESS) return nRet; wsprintf(szMsg, TEXT("Layer Retrieved\nName[%s]\nSize[%d]\nLocked[%d]\nVisible[%d]"), LayerDesc.szName, LayerDesc.nSize, LayerDesc.bLocked, LayerDesc.bVisible ); } else { wsprintf(szMsg, TEXT("Layer Not Found")); return nRet; } MessageBox(NULL, szMsg, TEXT(""), MB_OK); return SUCCESS; }