Change region border properties (width, color etc)

Hi,

Is there any way I could change the properties of a region border (region implemented with LBitmapRgn) like color and border width?
I didn't find anything in the documentation but maybe there is a not-so-obvious way to do it.

Thanks,
Arg

Arg,

There is no direct way to do
that using LEADTOOLS functions. However, you might be able to implement your
own solution based on the LBitmapRgn::GetClipSegments function. To do this, get
all segments and draw the needed pixels at the desired color and weight at the 2 ends of each segment.

GetClipSegments will return the pixel coordinates relative to the image. How can I get the region border pixels relative to the display (taking into account zoom, scale, rotate etc)?

As a side note I'm using LImageViewer to display the image.

Thanks

I checked your question again and there's actually a better function to use, which is LBitmap::GetRgnContourPoints.

About converting the
resulting points to display coordinates, how exactly are you displaying the image? (which LEADTOOLS object or functions are you using)?

I'm displaying the DICOM image by inserting it in a cell of LImageViewer. I also specify that I want it to fit the container window.

I guess the real question is: how can I retrieve the display coordinates of any given image pixel at any moment using LImageViewer?

Arg,

I have looked in LEADTOOLS
help files and found some useful information regarding Translating Coordinates, please read these topics:

- Translating Coordinates for a Bitmap Region.

- RGNXFORM.

Please let me know if you need further assistance.

I already checked those topics and I couldn't find an answer to this question. That's why I posted this message.

- GetRgnXForm always returns RGNXFORM with all members set to 0

LBitmap bitmap(&hBitmap); // bitmap is a valid bitmap
LBitmapRgn rgn(&bitmap); //rgn is a valid region

RGNXFORM xForm;
rgn.GetRgnXForm(&xf);

xf has all values set to 0

-PointFromBitmap which should translate the coordinates from bitmap to display doesn't seem to work. The coordinates pased to the function are always unchanged:

LBitmap bitmap(&hBitmap);
int x = 100;
int y = 100;
bitmap.PointFromBitmap(1, &x, &y);

x and y are unchanged although the image is resized to fit the display. Same thing happens if the image is rotated.

I am using LImageViewer to display the image so this may affect the way these API functions work.
I would appreciate any help to solve this issue.

Arg,

The LImageViewer control
does not work like the rest of our Class Library. This means if you use it to
display images, normal region and painting functions will not be available to you.