Welcome Guest! To enable all features, please Login or Register.

Notification

Icon
Error

Options
View
Last Go to last post Unread Go to first unread post
#1 Posted : Thursday, November 6, 2008 2:21:12 PM(UTC)
JoeBussell

Groups: Registered
Posts: 15


Is there a means of getting the rotation angle that the deskew method found when transforming an image?
 

Try the latest version of LEADTOOLS for free for 60 days by downloading the evaluation: https://www.leadtools.com/downloads

Wanna join the discussion? Login to your LEADTOOLS Support accountor Register a new forum account.

#2 Posted : Friday, November 7, 2008 7:56:43 AM(UTC)

jigar  
Guest

Groups: Guests
Posts: 3,022

Was thanked: 2 time(s) in 2 post(s)

Yes there is a way of doing it.  What toolkit version are you using?  What language are you programming in?  In the API there is a parameter that you pass in the L_DeskewBitmap() function which is updated with the angle.  In .NET there is an Angle property that is updated.
 
#3 Posted : Friday, November 7, 2008 11:37:21 AM(UTC)
JoeBussell

Groups: Registered
Posts: 15


14.5 OCX
 
#4 Posted : Monday, November 10, 2008 6:47:26 AM(UTC)

jigar  
Guest

Groups: Guests
Posts: 3,022

Was thanked: 2 time(s) in 2 post(s)

The DeskewAngle property is not available in the 14.5 ActiveX, but it is available in the COM objects (LEADRasterProcess.DeskewAngle).  If you have the COM Objects, then you can use the Deskew() method from LEADRasterProcess instead of the LEAD Main control.
 
You cannot post new topics in this forum.
You cannot reply to topics in this forum.
You cannot delete your posts in this forum.
You cannot edit your posts in this forum.
You cannot create polls in this forum.
You cannot vote in polls in this forum.

Powered by YAF.NET | YAF.NET © 2003-2024, Yet Another Forum.NET
This page was generated in 0.041 seconds.