LVectorBase::GetLayerByIndex

Summary

Gets the layer at the specified index in the class object's vector handle.

Syntax

#include "ltwrappr.h"

virtual L_INT LVectorBase::GetLayerByIndex(nIndex, pVectorLayer)

Parameters

const L_INT nIndex

Index of the requested layer. This index is zero-based. Possible values are between 0 and LVectorBase::GetLayerCount - 1.

LVectorLayer * pVectorLayer

Pointer to an LVectorLayer object to be updated, if the layer is found. If the layer is not found, this function will return ERROR_VECTOR_LAYER_NOT_FOUND.

Returns

Value Meaning
SUCCESS The function was successful.
< 1 An error occurred. Refer to Return Codes.

Comments

To determine the number of layers in a vector handle, call LVectorBase::GetLayerCount.

To get a layer, given the name of the layer, use LVectorBase::GetLayerByName.

Required DLLs and Libraries

See Also

Functions

Topics

Example

L_INT LVectorBase__GetLayerByIndexExample(HWND hWnd, LVectorBase *pVector) 
{ 
   UNREFERENCED_PARAMETER(hWnd); 
 
   //LVectorBase Vector; 
   //Vector.Load("test.dxf");    
 
   L_INT          nRet; 
   LVectorLayer   VectorLayer; 
   L_TCHAR        szMsg[100]; 
 
   //Get the first layer 
   nRet = pVector->GetLayerByIndex(0, &VectorLayer); 
   if (nRet == SUCCESS) 
   { 
      VECTORLAYERDESC LayerDesc; 
 
      nRet = VectorLayer.GetLayerDesc(&LayerDesc); 
      if(nRet != SUCCESS) 
         return nRet; 
 
      wsprintf(szMsg, TEXT("Layer Retrieved\nName[%s]\nSize[%d]\nLocked[%d]\nVisible[%d]"), 
               LayerDesc.szName, 
               LayerDesc.nSize, 
               LayerDesc.bLocked, 
               LayerDesc.bVisible 
               ); 
   } 
   else 
   { 
      wsprintf(szMsg, TEXT("Layer Not Found")); 
 
      return nRet; 
   } 
   MessageBox(NULL, szMsg, TEXT(""), MB_OK); 
 
   return SUCCESS; 
} 
Help Version 22.0.2022.12.7
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LEADTOOLS Vector C++ Class Library Help
Products | Support | Contact Us | Intellectual Property Notices
© 1991-2023 LEAD Technologies, Inc. All Rights Reserved.